第OpenCV繪制圓端矩形的示例代碼目錄功能函數(shù)測試代碼測試效果本文主要介紹了OpenCV繪制圓端矩形的示例代碼，分享給大家，具體如下:

功能函數(shù)

//繪制圓端矩形（藥丸狀，pill）

voidDrawPill(cv::Matmask,constcv::RotatedRectrotatedrect,constcv::Scalarcolor,intthickness,intlineType)

cv::Matcanvas=cv::Mat::zeros(mask.size(),CV_8UC1);

//確定短邊，短邊繪制圓形

cv::RotatedRectrect=rotatedrect;

floatr=rect.size.height/2.0f;

if(rect.size.widthrect.size.height){

rect.size.width-=rect.size.height;

else{

rect.size.height-=rect.size.width;

r=rect.size.width/2.0f;

cv::Point2fps[4];

rect.points(ps);

//繪制邊緣

std::vectorstd::vectorcv::PointtmpContours;

std::vectorcv::Pointcontours;

for(inti=0;i!=4;++i){

contours.emplace_back(cv::Point2i(ps[i]));

tmpContours.insert(tmpContours.end(),contours);

drawContours(canvas,tmpContours,0,cv::Scalar(255),5,lineType);//填充mask

//計算常長短軸

floata=rotatedrect.size.width;

floatb=rotatedrect.size.height;

intpoint01_x=(int)((ps[0].x+ps[1].x)/2.0f);

intpoint01_y=(int)((ps[0].y+ps[1].y)/2.0f);

intpoint03_x=(int)((ps[0].x+ps[3].x)/2.0f);

intpoint03_y=(int)((ps[0].y+ps[3].y)/2.0f);

intpoint12_x=(int)((ps[1].x+ps[2].x)/2.0f);

intpoint12_y=(int)((ps[1].y+ps[2].y)/2.0f);

intpoint23_x=(int)((ps[2].x+ps[3].x)/2.0f);

intpoint23_y=(int)((ps[2].y+ps[3].y)/2.0f);

cv::Pointc0=abcv::Point(point12_x,point12_y):cv::Point(point23_x,point23_y);

cv::Pointc1=abcv::Point(point03_x,point03_y):cv::Point(point01_x,point01_y);

//長軸兩端以填充的方式畫圓，直徑等于短軸

cv::circle(canvas,c0,(int)r,cv::Scalar(255),5,lineType);

cv::circle(canvas,c1,(int)r,cv::Scalar(255),5,lineType);

//繪制外圍輪廓，如果不這樣操作，會得到一個矩形加兩個圓形，丑。。。

std::vectorstd::vectorcv::PointEXcontours;

cv::findContours(canvas,EXcontours,cv::RETR_EXTERNAL,CHAIN_APPROX_SIMPLE);

drawContours(mask,EXcontours,0,color,thickness,lineType);//填充mask

}

測試代碼

#includeiostream

#includeopencv2/opencv.hpp

usingnamespacestd;

usingnamespacecv;

voidDrawPill(cv::Matmask,constcv::RotatedRectrotatedrect,constcv::Scalarcolor,intthickness,intlineType);

intmain()

cv::Matsrc=imread("test.jpg");

cv::Matresult=src.clone();

cv::RotatedRectrorect(cv::Point(src.cols/2,src.rows/2),cv::Size(1000,800),50);

DrawPill(result,rorect,cv::Scalar(0,255,255),8,16);

imshow("original",src);

imshow("result",result);

waitKey(0);

return0;

//繪制圓端矩形（藥丸狀，pill）

voidDrawPill(cv::Matmask,constcv::RotatedRectrotatedrect,constcv::Scalarcolor,intthickness,intlineType)

cv::Matcanvas=cv::Mat::zeros(mask.size(),CV_8UC1);

//確定短邊，短邊繪制圓形

cv::RotatedRectrect=rotatedrect;

floatr=rect.size.height/2.0f;

if(rect.size.widthrect.size.height){

rect.size.width-=rect.size.height;

else{

rect.size.height-=rect.size.width;

r=rect.size.width/2.0f;

cv::Point2fps[4];

rect.points(ps);

//繪制邊緣

std::vectorstd::vectorcv::PointtmpContours;

std::vectorcv::Pointcontours;

for(inti=0;i!=4;++i){

contours.emplace_back(cv::Point2i(ps[i]));

tmpContours.insert(tmpContours.end(),contours);

drawContours(canvas,tmpContours,0,cv::Scalar(255),5,lineType);//填充mask

//計算常長短軸

floata=rotatedrect.size.width;

floatb=rotatedrect.size.height;

intpoint01_x=(int)((ps[0].x+ps[1].x)/2.0f);

intpoint01_y=(int)((ps[0].y+ps[1].y)/2.0f);

intpoint03_x=(int)((ps[0].x+ps[3].x)/2.0f);

intpoint03_y=(int)((ps[0].y+ps[3].y)/2.0f);

intpoint12_x=(int)((ps[1].x+ps[2].x)/2.0f);

intpoint12_y=(int)((ps[1].y+ps[2].y)/2.0f);

intpoint23_x=(int)((ps[2].x+ps[3].x)/2.0f);

intpoint23_y=(int)((ps[2].y+ps[3].y)/2.0f);

cv::Pointc0=abcv::Point(point12_x,point12_y):cv::Point(point23_x,point23_y);

cv::Pointc1=abcv::Point(point03_x,point03_y):cv::Point(point01_x,point01_y);

//長軸兩端以填充的方式畫圓，直徑等于短軸

cv::circle(canvas,c0,(int)r,cv::Scalar(255),5,lineType);

cv::circle(canvas,c1,(int)r,cv::Scalar(255),5,lineType);

//繪制外圍輪廓，如果不這樣操作，會得到一個矩形加兩個圓形，丑。。。

std::vectorstd::vectorcv::PointEXcontours;

cv::findContours(canvas,EXcontours,cv::RETR_EXTERNAL,CHAIN_APPROX_SIMPLE);

drawContours(mask,EXcontours,0,color,thickness,lineType);//填充mask

}

測試效果

圖1